How do you solve #2/5=(y-26)/(y+11)#?

3 Answers
Apr 8, 2018

#152/3#

Explanation:

First, multiply both sides by #5(y+11)# to get rid of all denominators.

#2/cancel5 times cancel5(y+11)=(y-26)/cancel((y+11)) times 5cancel((y+11))#

Now simplify to get: #2(y+11)=5(y-26)#

Now multiply both sides out. #2y+22=5y-130#

Now place constants on the same side and the variables on the same side. #3y=152#

Now, just divide both side by 3 and you get your answer.

#y=152/3#

Now, 152 does not evenly divide by three, so we can present it as an improper fraction (#152/3#) or a mixed fraction (#50 2/3#).

Apr 8, 2018

#y = 50 2/3 ~~50.7#

Explanation:

#2/5 = (y - 26)/(y + 11)#

First, cross multiply;

#2(y + 11) = 5(y - 26)#

Secondly, eliminate the brackets;

#2y + 22 = 5y - 130#

Thirdly, collect like terms;

#2y - 5y = - 130 - 22#

#-3y = - 152#

Divide both sides by #-3#

#(-3y)/(-3) = (-152)/(-3)#

#(cancel(-3)y)/cancel(-3) = (cancel-152)/(cancel-3)#

#y = 152/3#

#y = 50 2/3 ~~50.7#

Apr 8, 2018

#y=152/3#

Explanation:

=#2/5=(y-26)/(y+11)#

=#2y+22=5y-130#

=#5y-2y=130+22#

=#3y=152#

=#y=152/3#

Hope it helps!