Simplify #sec(Theta+pi)# ?
1 Answer
Apr 8, 2018
Explanation:
Recall that
#sec(theta + pi) = 1/(costhetacospi - sinthetasinpi) = 1/(-costheta) = -sectheta#
Hopefully this helps!
Recall that
#sec(theta + pi) = 1/(costhetacospi - sinthetasinpi) = 1/(-costheta) = -sectheta#
Hopefully this helps!