The force applied against a moving object travelling on a linear path is given by #F(x)= x^2+4x#. How much work would it take to move the object over #x in [0,2] #?

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Answer 1 · 2018-04-09T16:43:36

The work is #=32/3J#

The work done

#DeltaW=FDeltax#

THe force is #F(x)=x^2+4x#

#W=int_0^2(x^2+4x)dx#

#=[1/3x^3+2x^2]_0^2#

#=(8/3+8)-(0+0)#

#=32/3J#