How do you solve #2x^2+11x+5=0#?
1 Answer
Apr 11, 2018
Explanation:
#"using the a-c method to factorise"#
#"consider the factors of the product "2xx5=10#
#"which sum to + 11"#
#"the required factors are + 10 and + 1"#
#"split the middle term using these factors"#
#2x^2+10x+x+5=0larrcolor(blue)"factor in groups"#
#rArrcolor(red)(2x)(x+5)color(red)(+1)(x+5)=0#
#"take out the common factor "(x+5)#
#rArr(x+5)(color(red)(2x+1))=0#
#"equate each factor to zero and solve for x"#
#x+5=0rArrx=-5#
#2x+1=0rArrx=-1/2#