How do you find the slant asymptote of #y=(x^2)/(2x^2-8)#?

1 Answer
VNVDVI
Apr 12, 2018

No slant asymptote exists, but there is the horizontal asymptote #y=1/2.#

Explanation:

The numerator and denominator are of the same degree (degree #2#) -- no slant asymptote exists in such cases.

Rather, there is a horizontal asymptote given by dividing the coefficients of the leading terms (terms of highest degree), in this case, #y=1/2.#

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