How do you factor the trinomial #x²+8x+15#?

2 Answers
Apr 13, 2018

#(x+3)(x+5)#

Explanation:

First, find the factors of 15.
#15=1*15=3*5#
Now, split 8x into 2 terms of "x"s containing the numbers 1 and 15 or 3 and 5.
#x+15x!=8x#, but #3x+5x=8x#
Now we have #x^2+3x+5x+15#.
Next factor x from #x^2# and #3x#.
#x(x+3)#
Also factor 5 from #5x# and #15#.
#5(x+3)#
We can notice that #x(x+3)# and #5(x+3)# both contain #(x+3)#. Since they both also multiply we can say that the answer is #(x+3)(x+5)#.

Apr 13, 2018

#(x+5)(x+3)#

Explanation:

Do it backwards to double check.

FOIL

First: x times x is #x^2#
Outer: x times 3 is #3x#
Inner: x times 5 is #5x#
Last: 5 times 3 is #15#

Add like terms: #x^2# + #(3x + 5x)# + #15#

Final answer: #x^2# + #8x# + #15#