How do you simplify #1/sqrt(32)#?

2 Answers
Apr 13, 2018

#sqrt(2)#/8

Explanation:

  1. rationalize your denominator by multiplying the entire fraction by #sqrt(32)#
  2. you should now have #sqrt(32)#/32
  3. now simplify your numerator " #sqrt(32)# ," you should get 4#sqrt(2)#
  4. your new fraction should be 4#sqrt(2)#/32
  5. simplify your fraction #fr(4/32)#
  6. final answer should be #sqrt(2)#/8

#1/sqrt32=sqrt2/8#

Explanation:

Here,# 1/sqrt32#
#= 1/sqrt((2^2)^2*2)#
#=1/(4sqrt2)*sqrt2/sqrt2#

#=sqrt2/8#