Question

What is the equation of the line perpendicular to `y=-3/7x` that passes through `(8,5)`?

Answer 1

y = `7/3x - 41/3`

Explanation:

For perpendicular lines, the product of their slopes is -1
The slope of the line is `-3/7`
Hence, the slope of the line perpendicular is ( `-1/(-3/7)`) = `7/3`
`y-y1 = m(x-x1)`
y-5 = `7/3`(x - 8)
y = `7/3x - 56/3 +5`
y = `7/3x - 41/3`