Question

How do you find the numerical value of one trigonometric function of x if tan x/cot x - sec x/cos x = 2/csc x ???

Answer 1

210 degree

Explanation:

Given, `(tanx)/(cotx)-(secx)/(cosx)=2/cscx`
`rArr tanx/(1/tanx)-sec/(1/secx)=2sinx`
`rArr tan^2x-sec^2x=2sinx`[As `sec^2x-tan^2x = 1]`
`rArr -1=2sinx`
`rArr sinx = -1/2`
`rArr sinx = sin(180+30)`
`rArr x=210`