How do you find the derivative of #8x^2+9x+12#?

2 Answers
Apr 14, 2018

#d/dx[8x^2+9x+12]=16x+9#

Explanation:

Remember that:

#d/dx[x^n]=nx^(n-1)# if #n# is a constant.

Therefore, the derivative is:

#8*2x^(2-1)+9*1*x^(1-1)+12*0*x^(0-1)#

#=>16x^(1)+9x^(0)+0#

#=>16x+9#

That is the answer!

Apr 14, 2018

#16x+9#

Explanation:

#"differentiate each term using the "color(blue)"power rule"#

#•color(white)(x)d/dx(ax^n)=nax^(n-1)#

#rArrd/dx(8x^2+9x+12)=16x+9#