Question

What is `lim_(xrarroo) ((6x) / e^x)`?

Answer 1

The limit equals `0`

Explanation:

Since we're of the form `oo/oo`, we may apply l'hospitals.

`L = lim_(x->oo) 6/e^x`

`L = lim_(x->oo) 6e^(-x)`

Since `e^-x` converges to `0` as `x -> oo`, we can say

`L = 0`

Hopefully this helps!