How do you condense #log_10 x - 4log_10 y#?
1 Answer
Apr 16, 2018
Explanation:
#"using the "color(blue)"laws of logarithms"#
#•color(white)(x)logx^nhArrnlogx#
#rArr4log_(10)y=log_(10)y^4#
#•color(white)(x)logx-logyhArrlog(x/y)#
#rArrlog_(10)x-log_(10)y^4=log_(10)(x/y^4)#