Question

How do you add or subtract `5/(4x^2y) – y/(14xz)`?

Answer 1

We begin by trying to find a common denominator for these two fractions....
1) The two denominators that we are working with are `4x^2y`and `14xz`
2) To find the LCD we must factor out the two numbers
`14xz = 2 *7 *x*z`
`4x^2y=2^2*x^2*y`
3) Then we find the product of each factor with the highest power
`(2^2)(x^2)(7)(y)(z) = 28x^2yz`

Then we try to set each denominator to the LCD that we found `(28x^2yz)/(28x^2yz)` 28x^2yz)/(28x^2yz)
4) `(5)/(4x^2y)*(7z)/(7z) = (35z)/(28x^2yz)`

`y/(14xz) * (2xy)/(2xy) = (2xy^2)/(28x^2yz)`

Now since we have a common denominator, we can now simply the equation into one fraction
`(35z-2xy^2)/(28x^2yz)`
That took forever to write out on this,,,