How do you solve #n/(7-n)+3/5=1#?

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Answer 1 · 2018-04-17T10:24:30

#n = 2#

#n/(7-n) + 3/5 = 1#

# n/(7-n) + color(red)(cancel(color(black)(3/5) -3/5)) = 1 color(red)(-3/5)#

#n/(7-n) = 5/5 - 3/5 #

#n/(7-n) = 2/5#

We can cross multiply here.

#n xx 5 = 2 xx (7-n)#

#5n color(red)( +2n)= 14 color(red)(cancel(color(black)(-2n) +2n))#

#(color(red)(cancel(7))n)/color(red)(cancel(7)) = 14/color(red)(7)#

#color(blue)(n = 2)#