How do you multiply #(2b^2-2c^2)^2#?
1 Answer
Apr 19, 2018
#4b^4-8b^2c+4c^2#
Explanation:
Given -
#(2b^2- 2c)^2#
#(2b^2- 2c)(2b^2- 2c)#
#2b^2(2b^2)-2c(2b^2)+2b^2(-2c)-2c(-2c)#
#4b^4-4b^2c-4b^2c+4c^2#
#4b^4-8b^2c+4c^2#