Let #f(x)=1-x# and #g(x)= x^2# and #h(x)= 1/x#, how do you find g(f(h(x)))?
1 Answer
Apr 19, 2018
Explanation:
#"we can break this composition into parts"#
#"evaluate "(f(h(x))" to begin with"#
#rArrf(h(x))=f(1/x)=1-1/x#
#rArrg(f(h(x)))#
#=g(1-1/x)=(1-1/x)^2=1-2/x+1/x^2#