What is the Cartesian form of #( -2 , ( 7pi)/3 ) #?

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Answer 1 · 2018-04-20T02:40:21

The Cartesian form is #(-1, -sqrt(3))#

#x=rcostheta#

#=-2cos((7pi)/3)#

#=-2cos((7pi)/3-2pi)#

#=-2cos((7pi-6pi)/3)#

#=-2cos(pi/3)#

#=-2(1/2)=-1#

#y=rcostheta#

#=-2sin((7pi)/3)=-2sin(pi/3)=-2(sqrt(3)/2)=-sqrt(3)#

The Cartesian form is #(-1, -sqrt(3))#