How do you write an equation that contains points (4, -1) and (-2, -13)?
1 Answer
Apr 20, 2018
Explanation:
#"the equation of a line in "color(blue)"slope-intercept form"# is.
#•color(white)(x)y=mx+b#
#"where m is the slope and b the y-intercept"#
#"to calculate m use the "color(blue)"gradient formula"#
#•color(white)(x)m=(y_2-y_1)/(x_2-x_1)#
#"let "(x_1,y_1)=(4,-1)" and "(x_2,y_2)=(-2,-13)#
#rArrm=(-13-(-1))/(-2-4)=(-12)/(-6)=2#
#rArry=2x+blarrcolor(blue)"is the partial equation"#
#"to find b substitute either of the 2 given points into"#
#"the partial equation"#
#"using "(4,-1)" then"#
#-1=8+brArrb=-1-8=-9#
#rArry=2x-9larrcolor(red)"is equation of line"#