How do you write an equation in standard form for a line with a slope of 1/4 and goes through point (4, 0)?

1 Answer
Apr 20, 2018

#x-4y=4#

Explanation:

#"the equation of a line in "color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#

#"where A is a positive integer and B, C are integers"#

#"to begin express the equation in "color(blue)"point-slope form"#

#•color(white)(x)y-y_1=m(x-x_1)#

#"where m is the slope and "(x_1,y_1)" a point on the line"#

#"here "m=1/4" and "(x_1,y_1)=(4,0)#

#rArry=1/4(x-4)#

#rArry=1/4x-1#

#"multiply all terms by 4"#

#rArr4y=x-4#

#rArrx-4y=4larrcolor(red)"in standard form"#