How do you solve #x^2 + 5x = 0#?

Question

74360 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-21T06:43:11

#x_1 = 0#
#x_2 = -5#

#x^2 + 5x = 0#
#x(x+5) = 0#

By the null factor law either #x# or #x+5# must be equal to #0#.

#x_1 = 0#
#x_2 = -5#

Answer 2 · 2018-04-21T07:59:16

#x=-5" or "x=0#

#"take out a "color(blue)"common factor "x#

#rArrx(x+5)=0#

#"equate each of the factors to zero and solve for x"#

#rArrx=0#

#x+5=0rArrx=-5#