How do you factor #6x^2=8x+8#?

1 Answer
Apr 21, 2018

The factored form is #(3x+2)(x-2)=0#.

Explanation:

First, put everything on one side of the equation:

#6x^2=8x+8#

#6x^2-8x=8#

#6x^2-8x-8=0#

Factor out a #2#:

#2(3x^2-4x-4)=0#

Factor by grouping:

#2(3x^2-6x+2x-4)=0#

#2(3x(x-2)+2x-4)=0#

#2(3x(x-2)+2(x-2))=0#

#2(3x+2)(x-2)=0#

That's the factored polynomial. Hope this helped!