What is the slope of the line passing through #(-3,4)# and #(6,1)#?

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Answer 1 · 2018-04-21T19:26:04

#m = -1/3#

The slope of the line between #A(x_1, y_1) and B(x_2, y_2)# is:
#m = (y_2 - y_1)/(x_2-x_1)#

#(-3, 4) and (6, 1):#

#m = (4 - 1)/(-3 - 6) = 3/-9 = -1/3#

Answer 2 · 2018-04-21T19:27:15

see a solution process below;

Recall equation of a straight line;

#y = mx + c#

Where;

#m -> "slope"#

Points; #(-3, 4) and (6, 1)#

Also recall;

#m = (y_2 - y_1)/(x_2 - x_1)#

Where;

#x_1 = -3#

#x_2 = 6#

#y_1 = 4#

#y_2 = 1#

Now inputting the values into the equation;

#m = (y_2 - y_1)/(x_2 - x_1)#

#m = (1 - 4)/(6 - (-3))#

#m = (-3)/(6 + 3)#

#m = (-3)/(9)#

#m = - 1/3#

Hope this helps!