What is the y intercept of #-2y=3x^2-3#?

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Answer 1 · 2018-04-22T02:45:41

The y-intercept is #(0,3/2)# or #(0,1.5)#.

Given:

#-2y=3x^2-3#

The y-intercept is the value of #y# when #x=0#. Substitute #0# for #x# in the equation and solve for #y#.

#-2y=3(0)^2-3#

#-2y=-3#

Divide both sides by #-2#.

#y=(-3)/(-2)#

#y=3/2#

The y-intercept is #(0,3/2)# or #(0,1.5)#.

This is also the vertex for this particular parabola.

graph{-2y=3x^2-3 [-10, 10, -5, 5]}