How do you find the domain of h(x)= 1/(x+1)h(x)=1x+1?

1 Answer
Apr 22, 2018

All real numbers excluding x=-1x=1; (-oo, -1) U (-1,oo)(,1)U(1,)

Explanation:

The domain includes all values of xx for which h(x)h(x) exists.

For rational functions (such as this one), the domain doesn't exist for values of xx which cause division by 0.0. So, let's determine which values of xx cause the denominator to equal 0:0:

x+1=0x+1=0

x=-1x=1.

Then, the domain is all values of xx excluding x=-1.x=1. In interval notation,

(-oo, -1) U (-1,oo)(,1)U(1,)