Question

How do you find the domain of `h(x)= 1/(x+1)`?

Answer 1

All real numbers excluding `x=-1`; `(-oo, -1) U (-1,oo)`

Explanation:

The domain includes all values of `x` for which `h(x)` exists.

For rational functions (such as this one), the domain doesn't exist for values of `x` which cause division by `0.` So, let's determine which values of `x` cause the denominator to equal `0:`

`x+1=0`

`x=-1`.

Then, the domain is all values of `x` excluding `x=-1.` In interval notation,

`(-oo, -1) U (-1,oo)`