How do you simplify #(8a + 1) ( 2a - 3) - ( 4a - 5)^{2}#?

Question

1209 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-23T12:47:28

I use FOIL: #(8a+1)(2a -3)-(4a -5)^2##= 16 a^2 - 24 a + 2a -3 - (16a^2 - 40a + 25)##=18 a - 28#