How do you solve #25a=10a^2#?

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Answer 1 · 2018-04-24T23:50:44

#=>a=5/2 #

We are given

#25 a = 10a^2#

First we divide both sides by #a#:

#(25cancela)/cancela = (10a^cancel(2))/cancela#

#25 = 10a#

Then we divide both sides by #10#:

#25/10 = (cancel(10)a)/cancel(10)#

#5/2 = a#

Answer 2 · 2018-04-24T23:51:21

#a=0,5/2#

We can start by subtracting #25a# from both sides to get

#10a^2-25a=0#

We can factor out a #5a# to get

#5a(2a-5)=0#

We now set both factors equal to zero:

#5a=0=>color(blue)(a=0)#

#2a-5=0=>2a=5=>color(blue)(a=5/2)#

Hope this helps!