How do you simplify $(6 + 6^2) times 3$ using order of operations?

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Answer 1 · 2018-04-25T00:08:07

$=126$

$(6+6^2) xx 3$

$=(6 + 36) xx 3$

$= (42) xx 3$

$=126$

BEDMAS. Brackets go first, which is $6 + 6^2$ . Inside the brackets, exponents go next, which turns the $6^2$ to a $36$ , which gives you $(6+36)$ .

Then, to finalize the brackets, add them together. Then all you have left is $42$ multiplied by $3$ , which gives you $126$ .

How do you simplify (6 + 6^2) times 3(6 + 6^2) times 3 using order of operations?