How do you solve #x^2 = 49#?

Question

26886 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-25T23:33:49

#x=+-7#

Isolate the variable #x#:

#x^2=49#

#sqrt(x^2)=sqrt49#

#x=+-7#

Answer 2 · 2018-04-25T23:36:16

#x= +-7 #

So what you would do is you would find the square root both sides of the equation

#sqrt49=sqrtx#

which cancels out the #x^2#, leaving you with

#x = +-7 #