Question

How do you solve `w(4w+6)+2w=2(2w^2+7w-3)`?

Answer 1

`w = 1`

Explanation:

`w(4w + 6) + 2w = 2(2w^2 + 7w - 3)`

Use the Distributive Property:
`w(4w + 6) + 2w = 2(2w^2 + 7w - 3)`
`4w^2 + 6w + 2w = 4w^2 + 14w - 6`

Combine Like Terms:
`4w^2 + 6w + 2w = 4w^2 + 14w - 6`
`4w^2 + 8w = 4w^2 + 14w - 6`

Use the Additive Inverse:
`4w^2 + 8w = 4w^2 + 14w - 6`
`8w = 14w - 6`
`-6x = -6`
`w = 1`

There's your answer!