Question

How do you solve `(x - 2) ^ { 2} + 3= 4`?

Answer 1

`x=3 and x=1`

Explanation:

first expand the quadratic equation
`x^2-4x+4+3=4`
then sum all the unknown and the constant which will give you
`x^2-4x+3=0`
then factorise the equation and u get
`(x-3)(x-1)=0`
therefore `x=3 and x=1`

Answer 2

`x=1" or "x=3`

Explanation:

`"isolate "(x-2)^2" by subtracting 3 from both sides"`

`rArr(x-2)^2=4-3=1`

`color(blue)"take the square root of both sides"`

`sqrt((x-2)^2)=+-sqrt1larrcolor(blue)"note plus or minus"`

`rArrx-2=+-1`

`"add 2 to both sides"`

`rArrx=2+-1`

`rArrx=2-1" or "x=2+1`

`rArrx=1" or "x=3`