How do you solve #5r ^ { 2} + 10r = 0#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer EZ as pi Apr 28, 2018 #r=0" " or" " r=-2# Explanation: #5r^2 + 10r =0# #5r(r+2)=0# #5r=0" or "(r+2)=0# If #5r=0, " then, " r=0# If #(r+2)=0, " then, " r=-2# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1322 views around the world You can reuse this answer Creative Commons License