Question

How do you solve `5(3x + 12) = -15`?

Answer 1

`x=-5`

Explanation:

`"divide both sides by "5`

`cancel(5)/cancel(5)(3x+12)=(-15)/5`

`rArr3x+12=-3`

`"subtract 12 from both sides"`

`3xcancel(+12)cancel(-12)=-3-12`

`rArr3x=-15`

`"divide both sides by 3"`

`(cancel(3) x)/cancel(3)=(-15)/3`

`rArrx=-5`

`color(blue)"As a check"`

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

`5(-15+12)=5xx-3=-15=" right side"`

`rArrx=-5" is the solution"`