Question

How do you find the derivative for `sqrt(2x^3 - 3x- 4)`?

Answer 1

`(6x^2-3)/(2sqrt(2x^3-3x-4))`

Explanation:

By using the chain rule

IF F(x)=f(g(x))

THEN F'(x)=f'(g(x))*g'(x)

`d/(dx) sqrt(2x^3-3x-4)=1/(2sqrt(2x^3-3x-4))times(6x^2-3)`

=`(6x^2-3)/(2sqrt(2x^3-3x-4))`