How do you find the x and y intercepts for #y=2/3x-8#?

1 Answer
Apr 29, 2018

#"x-intercept "=12," y-intercept "=-8#

Explanation:

#"to find the intercepts, that is where the graph crosses"#
#"the x and y axes"#

#• " let x = 0, in the equation for y-intercept"#

#• " let y = 0, in the equation for x-intercept"#

#x=0rArry=0-8=-8larrcolor(red)"y-intercept"#

#y=0rArr2/3x-8=0#

#rArr2/3x=8rArrx=(8xx3)/2=12larrcolor(red)"x-intercept"#
graph{(y-2/3x+8)((x-0)^2+(y+8)^2-0.04)((x-12)^2+(y-0)^2-0.04)=0 [-20, 20, -10, 10]}