How do you solve #(x+3)/3 = 6/x#?

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Answer 1 · 2018-05-01T04:29:24

# x= 3 or x= -6 #

#{x+3}/3 = 6/x#

#x(x+3) = 6(3)#

# x^2 + 3x = 18#

#x^2 +3 x - 18 = 0#

# (x- 3)(x+6) = 0#

# x= 3 or x= -6 #

Check:

#x=3#

#{3+3}/3 = 2 #

#6/3 = 2 quad sqrt #

#{-6 + 3}/3= -1 #

#6/-6 = -1 quad sqrt #