How do you simplify #(5^2 * 2 - 8) ÷ [3(3^2 - 2)]#? Algebra Expressions, Equations, and Functions PEMDAS 1 Answer sankarankalyanam May 2, 2018 #color(blue)(=>2)# Explanation: #(5^2 * 2 - 8) / [3 * (3^2 -2)]# Following the order of operations #color(indigo)("PEMDAS"# #=> (5^2 * 2 - 8) / [3*3^2 - 3*2], color(red)("Removing bracket"# #=> (25 * 2 - 8) / [3*9 - 3*2], color(red)("expanding exponent"# #=>(50 - 8) / (27 - 6), color(red)("multiplying"# #=> 42 / 21, color(red)("removing braces"# #=> cancel(42)^color(blue)(2) / cancel 21 = 2# Answer link Related questions What is PEMDAS? How do you use PEMDAS? How do you use order of operations to simplify #3(7-2)-8#? What are common mistakes students make with PEMDAS? How do you evaluate the expression #5[8+(3-1)]-2#? How do you simplify the expression #4(30-(3+1)^2)#? How do you evaluate the expression #x^4+x# if x=2? Is it okay to add first before subtracting in #4-6+3#? How do you simplify #(-3)^2+12*5#? How do you simplify #(4-2)^3-4*8+21div3#? See all questions in PEMDAS Impact of this question 1325 views around the world You can reuse this answer Creative Commons License