Question

How do you solve `x^2-3x+2=0` using the quadratic formula?

Answer 1

`x_1=2 or x_2=1`

Explanation:

`x^2+px+q=0`
`x_(1,2)=-p/2+-sqrt((p/2)^2-q)`
`p=-3 and q=2`
`x_(1,2)=3/2+-sqrt(9/4-2)`
`x_1=3/2+1/2=2 or x_2=3/2-1/2=1`