How do you graph #y+4x=1#?

1 Answer
May 2, 2018

#y+4x=1#

#y=-4x+1#

enter image source here

#y=-4*(-5)+1=21#
#y=-4*(-2)+1=9#
#y=-4*(0)+1=1#
#y=-4*(2)+1=-7#
#y=-4*(5)+1=-19#

We can now draw a line through the coordinates,
#(-5,21), (-2,9), (0,1), (2,-7), (5,-19)#

enter image source here

Explanation:

Let everything #y# should be equal to on one side. Giving,

#y=-4x+1#

From there, make a table for your calculations. One for #x# values and the other for what #y# gives after replacing the #x# values with numbers.

Since #x# can be anything, and will go on infinitely. We can make up numbers to what #x# can be at certain times. In the table above, I have chosen #x# to be #-5, -2, 0, 2, 5# and seen what happen when I replaced these numbers with #x# in #y=-4x+1#.

One calculation will for example be,
#y=-4*(-5)+1=21#
Which basically means that when #x=-5# the #y#-axis will be at #21#.

Another is ,
#y=-4*(2)+1=-7#
Which means that when we choose #x=2# we will get a point on the #y#-axis being #-7#.

This is something we can see on the graph above too. For example, when #x=0# then #y=1#.

Since this is a straight line, we would basically just need to points to draw our line between and out from. Since this line goes on to the infinite.