How do you solve # 2/3x=6#?

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Answer 1 · 2018-05-03T00:38:12

Multiply both sides by the reciprocal of the fraction on the left-hand side to get #x=9#

We will multiply both sides by the reciprocal of the fraction on the left-hand side. This will eliminate #x#'s coefficient and give us our answer:

#cancel(2/3)x cancel(color(red)(xx3/2))=6color(red)(xx3/2)#

#x=6xx3/2#

#x=6/1xx3/2#

#x=18/2#

#color(green)(x=9)#

Answer 2 · 2018-05-03T00:38:32

#x=9#

#2/3x=6 rarr# Divide both sides by #2/3#

#x=6/(2/3)#

#x=6*3/2#

#6*3/2=6/1*3/2=(3cancel(6))/1*3/cancel(2)=9/1=9#

#x=9#