An object is at rest at #(4 ,5 ,1 )# and constantly accelerates at a rate of #4/3 m/s^2# as it moves to point B. If point B is at #(7 ,9 ,6 )#, how long will it take for the object to reach point B? Assume that all coordinates are in meters.

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Answer 1 · 2018-05-03T06:55:49

The time is #=3.26s#

The distance #AB# is

#AB=sqrt((7-4)^2+(9-5)^2+(6-1)^2)=sqrt(9+16+25)=sqrt(50)m#

Apply the equation of motion

#s=ut+1/2at^2#

The initial velocity is #u=0ms^-1#

The acceleration is #a=4/3ms^-2#

Therefore,

#sqrt50=0+1/2*4/3*t^2#

#t^2=3/2sqrt50#

#t=sqrt(3/2sqrt50)=3.26s#