Question

How do you solve `-5<=4r+3`?

Answer 1

`r>= -2`

Explanation:

`"isolate "4r" by subtracting 3 from both sides"`

`-5-3<=4rcancel(+3)cancel(-3)`

`rArr-8<=4r`

`"divide both sides by 4"`

`(-8)/4<=cancel(4)/cancel(4) r`

`rArr-2<=r" or "r>= -2`

`r in[-2,oo)larrcolor(blue)"in interval notation"`