Question

What is the Cartesian form of `(33,(-pi)/8)`?

Answer 1

`((33sqrt(2+sqrt2))/2,(33sqrt(2-sqrt2))/2)~~(30.5,-12,6)`

Explanation:

`(r,theta)->(x,y);(x,y)-=(rcostheta,rsintheta)`

`r=33`
`theta=-pi/8`

`(x,y)=(33cos(-pi/8),33sin(-pi/8))=((33sqrt(2+sqrt2))/2,(33sqrt(2-sqrt2))/2)~~(30.5,-12,6)`