How do you graph #y = 3sin(2x - pi/2) + 1#?

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Answer 1 · 2018-05-04T03:47:05

As below.

Standard form of sinusoidal wave equation is

#color(crimson)(y = A sin (Bx - C) + D#

Given #y = 3 sin (2x - (pi/2)) + 1#

#Amplitude = |A| = 3#

#"Period " = (2pi) / |B| = (2pi) / 2 = pi#

#"Phase Shift " = -C / B = (pi/2) / 2 = pi/4 " to the right"#

#"Vertical Shift " = D = 1#

graph{3 sin(2x - (pi/2)) + 1 [-10, 10, -5, 5]}