How do you graph the line that passes through (2,-1) parallel to the line 2x+3y=6?

1 Answer
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May 5, 2018

y=-2/3x+1/3y=−23x+13

Explanation:

  1. First, we manipulate the given equation into y=mx+cy=mx+c to find the gradient.
    2x+3y=62x+3y=6
    3y=-2x+63y=−2x+6
    y=-2/3x+2y=−23x+2
    :. Gradient =-2/3

Since the lines are parallel, they have the same gradient.

  1. Form an equation for the line.
    Let the equation of the line be y-y_1=m(x-x_1).
    y-(-1)=-2/3(x-2)
    y=-2/3x+1/3
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