Question

How do you write an equation of a line going through (4,1) parallel to y=1/3x+3?

Answer 1

`x-3y-1=0`

Explanation:

When a line is parallel to another line, that means that their gradients are the same ie your new line will have the gradient `m=1/3` since `y=1/3x+3` is in the general form `y=mx+b` where m is the gradient

Using the point-gradient method,

`(y-1)=1/3(x-4)`

`3y-3=x-4`
`x-3y-1=0`