How do you evaluate #(x + 0) ( x + 2) ( x - 5)#?

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Answer 1 · 2018-05-05T12:39:11

#x^3-3x^2-10x#

#(x + 0) ( x + 2) ( x - 5)#

Simplify,

#x(x+2)(x-5)#

Expand parenthesis,

#x(x^2+2x-5x-10)#

Expand,

#x^3-3x^2-10x#