Question

How do you solve `log_5x + log_3 x=1`?

Answer 1

`x=1.9211`

Explanation:

`log_5x+log_3 x=1` can be written as

`logx/log5+logx/log3=1`

or `log3logx+log5logx=log3log5`

or `logx=(log3log5)/(log3+log5)`

or `x=10^((log3log5)/(log15))`

= `10^((0.4771*0.6990)/1.1761)`

= `10^0.2836`

= `1.9211`