A container with a volume of #6 L# contains a gas with a temperature of #250^o K#. If the temperature of the gas changes to #320 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2018-05-10T09:34:03

The new volume is #=7.68L#

Apply Charles' Law

#" Volume (L) "/" temperature (K) "= " constant"#, #"(at constant pressure")#

#V_1/T_1=V_2/T_2#

The initial volume is #V_1=6L#

The initial temperature is #T_1=250K#

The final temperature is #T_2=320K#

The final volume is

#V_2=T_2/T_1*V_1=320/250*6=7.68L#