How do you solve #- 2b + 9= 25#?

Question

1722 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-11T02:19:52

#b = -8#

#-2b + 9 = 25#

To solve for #color(blue)b#, we have to make it by itself.

To do so, first subtract #color(blue)9# from both sides of the equation:
#-2b + 9 quadcolor(blue)(-quad9) = 25 quadcolor(blue)(-quad9)#

#-2b = 16#

Now divide both sides by #color(blue)(-2)#:
#(-2b)/color(blue)(-2) = 16/color(blue)(-2)#

#b = -8#

Hope this helps!