How do you solve #\frac { 6( 5- z ) } { 5} = - z#?

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Answer 1 · 2018-05-11T05:15:07

#z=30#

Simplify the equation first:

#(6(5-z))/5=-z#

#(30-6z)/5=-z#

#30-6z=-zxx5#

#30-6z=-5z#

#-6z+5z=-30

#-Z=-30#

#z=-30/-1#
#z=30#